Solution to Quiz 3 (1,4)


Problem#1

New table for A will contain (-,6,5,11,7,8)
where 6,5, and 7 for B, C and E respectively are directly selected while for D it is min of (18,11,16) which is 11 and for F it is min of (8,15,11) which is 8.


Problem#4

Here Maximum output rate, M = 155 Mbps = 19.38 MB/sec
Token Arrival Rate = 84.8/(53x8) = 0.2 MB/sec.
Burst Time, S = 1msec.
Token Bucket Capacity, C = (19.38 - 0.2)x106x10-3 = 19.18 kB.


Other two Problems on the quiz:

Problem#2 What is fragmentation and why it is needed?

Problem#3 What is flood-based routing? Why flood-based routing will deliver the best performance if there was only one packet to transmit. Describe two methods to control a large number of duplicate packets.