Problem#2

Let's take a(alpha) = 0.9.
Then succesive estimates are 49, 50.1 and 50.09 msec respectively.

Problem#3

A sender may not send 255 TPDUs, i.e. 255 x 128 x 8 bits, in 30 sec. Thus maximum data rate = 255 x 128 x 8 / 30 = 8.704 kbps.

Problem#4

The first bursts contain 2 kB, 4kB, 8kB, 16 kB respectively. The next one is 30 kB and occurs after 80 msec.